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If the equation of a circle is (x - 2)2 + (y- 6)2 = 4, it passes through point (-4,6) (4,6) (2,6) (2,-6)

If the equation of a circle is (x - 2)2 + (y- 6)2 = 4, it passes through point (-4,6) (4,6) (2,6) (2,-6)
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If the equation of a circle is (x - 2)2 + (y- 6)2 = 4, it passes through point

(-4,6)
(4,6)
(2,6)
(2,-6)

asked
User Suresh Atta
by
8.5k points

1 Answer

3 votes
Photomath :)))))). I think is a
If the equation of a circle is (x - 2)2 + (y- 6)2 = 4, it passes through point (-4,6) (4,6) (2,6) (2,-6)-example-1
answered
User Koekenbakker
by
8.3k points
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