Question

What are the foci of the hyperbola whose equation is (x-6)^2/16-(y+7)^2/9= 1?

Answer 1

(1, -7) and (11, -7)

or A on edge

Explanation:

took the quiz

Answer 2

The foci of the hyperbola is (0,3) and (0,-3).

Explanation:

Given,

The equation of the hyperbola:
`((x-6)^(2) )/(16) -((y+7)^(2) )/(9) =1`

To find the foci of the given parabola

Formula

If the equation of the hyperbola:
`((x-h)^(2) )/(a^(2) ) -((y-k)^(2) )/(b^(2) ) =1`

The focus will be (0,±c) where c² = a²+b²

Now,

Here, a=3 and b=4

c² = 3²+4² = 25

or, c = ±5

Hence,

The foci of the hyperbola is (0,3) and (0,-3)