Register

What are the slopes of the asymptotes of a hyperbola with equation (y-2)^2/1^2 - (x-4)^2/3^2 = 1?

What are the slopes of the asymptotes of a hyperbola with equation (y-2)^2/1^2 - (x-4)^2/3^2 = 1?
asked 24.9k views
2 votes
What are the slopes of the asymptotes of a hyperbola with equation (y-2)^2/1^2 - (x-4)^2/3^2 = 1?

asked
User Jyanks
by
8.8k points

1 Answer

4 votes

Answer: 1/3 and -1/3

Explanation:

answered
User Elza
by
8.6k points
← Prev Question Next Question →

Related questions

User Satta
asked Aug 4, 2021 77.7k views
A hyperbola is represented using the equation (x-1)^2/4-(y+2)^2/16=1. What are the slopes of the asymptotes?
Satta asked Aug 4, 2021
by Satta
7.6k points
2 answers
4 votes
77.7k views
Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!