Answer:
Question incomplete
This is the complete question
You have a collection of 1.0 kΩ resistors.
How can you connect four of them to produce an equivalent resistance of 0.25 kΩ?
Step-by-step explanation:
Given that,
We have collection of resistor
R = 1.0 kΩ.
And we want to design an equivalent resistance of
R = 0.25kΩ
We know that,
Series connection of add up resistance and this increases the value of resistance, I.e
Req = R1 + R2 + R3 +.....
While
Parallel resistance add up the reciprocal of resistance and this reduces resistance
So, 1/Req = 1/R1 + 1/R2 + 1/R3 +......
Now, we want to design 0.25kΩ
Connect four of the resistor in parallel will give a equivalent resistance of 0.25 kΩ
1/Req = 1/R1 + 1/R2 + 1/R3 + 1/R4
R1 = R2 = R3 = R4 = 1.0 kΩ
1/Req = 1/1 + 1/1 + 1/1 + 1/1
1/Req = 1+1+1+1
1/Req = 4
Taking reciprocal of both sides..
Req = ¼ kΩ
This is the required equivalent resistance
So, connect the four of the resistor in parallel will give the required 0.25 kΩ resistance