Question

Two experiments were conducted in a bomb calorimeter. The first one to determine the heat capacity of the calorimeter, the second the heat of combustion of the carcinogenic substance benzene (C6H6). a. In the first experiment, the temperature rises from 22.37 o C to 24.68 o C when the calorimeter absorbs 5682 J of heat. Determine the heat capacity of the calorimeter.

Answer 1

Answer:
`2460J/g^0C`

Step-by-step explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

`Q=C* \Delta T`

Q = Heat absorbed by calorimeter =
`5682` Joules

C = heat capacity of calorimeter = ?

Initial temperature of the calorimeter =
`T_i` = 22.37°C

Final temperature of the calorimeter =
`T_f` = 24.68°C

Change in temperature ,
`\Delta T=T_f-T_i=(24.68-22.37)^0C=2.31^0C`

Putting in the values, we get:

`5682=C* 2.31^0C`

`C=2460J/g^0C`

The heat capacity of the calorimeter is
`2460J/g^0C`