Answer:
Total number of birds = 1024+512+64= 1600 
 
A. Frequency of GG birds = 1024/1600 = 0.64 
 
B. Frequency of Gg birds = 512/1600 = 0.32 
 
C. Frequency of gg birds = 64/1600 = 0.04 
 
D. According to Hardy Weinberg equilibrium 
 
G²+2Gg+g² = 1 or G+g = 1 
 
G² = 0.64 
 
G= √0.64 =0.8 
 
g² = 0.04 
 
g= √0.04 = 0.2 
 
A chi square test will help to know if the population is in Hardy Weinberg equilibrium.
Expected Observed Expected Deviation d² d²/E
ratio value (O) value (E) , d= O-E
 
0.8 1092 960 +132 17424 18.15 
0.2 108 240 -132 17424 72.6
Chi square, X² = 
 = 90.75 
 
Degree of freedom = n- 1= 2 - 1 = 1 
 
P value < 0.00001. So it's significant at C value of 0.05. 
 
Therefore, this population doesn't obey Hardy Weinberg equilibrium.