asked 188k views
3 votes
A study of the annual population of deer in Georgia from 1972-2012, shows the population, D(t), can be represented by the function D(t) = 394,267(1.032)^t

1 Answer

2 votes

Answer:


D(t)=394,267(1.003)^(12t)

Explanation:

The complete question in the attached figure

we have


D(t)=394,267(1.032)^t

This is a exponential growth function

where

P(t) is the population

t is the number of years

The initial value is 394,267 people

The factor growth is 1.032

To find out the monthly rate of growth, rewrite the expression

Remember that one year is equal to 12 months


D(t)=394,267(1.032)^{(t*(12)/(12))}


D(t)=394,267[(1.032)^{((1)/(12))}]^(12t)


D(t)=394,267(1.003)^(12t)

A study of the annual population of deer in Georgia from 1972-2012, shows the population-example-1
answered
User Nick Roz
by
8.4k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.