Question

A 1.1-kg uniform bar of metal is 0.40 m long and has a diameter of 2.0 cm. When someone bangs one end of this bar, a 1.5 MHz shock wave is travels along the length of the bar and reaches the other end in 0.12 ms. What is the wavelength of the shock wave in the metal?

Answer 1

`\lambda = 2.22* 10^(-3)\ m`

Step-by-step explanation:

Given,

mass of the bar = 1.1 Kg

length of rod, l = 0.40 m

diameter of the rod, d = 2 cm

frequency, f = 1.5 MHz

time, t = 0.12 ms

wavelength of the shock wave = ?

Speed of the wave =
`(L)/(t)=(0.40)/(0.12* 10^(-3))`

v = 3333.33 m/s

wavelength of the wave

`\lambda = (v)/(f)= (3333.33)/(1.5* 10^6)`

`\lambda = 2.22* 10^(-3)\ m`