asked 216k views
5 votes
What values of c and d make the equation true?


\sqrt[3]{162x^cy^5}=3x^2y(\sqrt[3]{6y^d}
RootIndex 3 StartRoot 162 x Superscript c Baseline y Superscript 5 Baseline EndRoot = 3 x squared y (RootIndex 3 StartRoot 6 y Superscript d Baseline EndRoot)

c = 2, d = 2

c = 2, d = 4

c = 6, d = 2

c = 6, d =4

asked
User Ghaleon
by
7.6k points

1 Answer

5 votes

Answer:

not d

Explanation:

edge

answered
User Mezo Istvan
by
8.1k points
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