Question

suppose the area of a square is x^2-10+25. What is the perimeter of the square? Hint* Find the length of the square first.

Answer 1

4x -20

Explanation:

The side length of the square is the square root of the area, so is ...

s^2 = (x^2 -10x +25) = (x -5)^2

s = (x -5)

Then the perimeter of the square is 4 times the side length:

P = 4(x -5)

P= 4x -20