Answer:
(v + 5)(2v + 1)
Explanation:
Given
2v² + 11v + 5
Consider the factors of the product of the coefficient of the v² term and the constant term which sum to give the coefficient of the v- term.
product = 2 × 5 = 10 and sum = + 11
The factors are + 10 and + 1
Use these factors to split the v- term
2v² + 10v + v + 5 ( factor the first/second and third/fourth terms )
= 2v(v + 5) + 1(v + 5) ← factor out (v + 5) from each term
= (v + 5)(2v + 1) ← in factored form