asked 219k views
3 votes
HURRY IM ON THE LAST 30 MINUTES OF MY TEST!!!! THANK YOU!!!

What are the vertices of the hyperbola whose equation is (x+7)^2/25-(y-8)^2/32= 1?(−13, 8) and (−1, 8)
(−12, 8) and (−2, 8)
(−7, 2) and (−7, 14)
(−7, 3) and (−7, 13)

asked
User Rawel
by
8.1k points

2 Answers

4 votes

Answer:

B) (-12,8) and (-2,8)

Explanation:

took the test

answered
User Loufi
by
7.9k points
2 votes

Answer:

B) (-12,8) and (-2,8)

Explanation:

x+7 was the first one so thats the number thats going to change

and the formula is (x-h) and (y-h) so the center will be (-7, 8)

when you add 5 which is the square root of a^2 (25) you get (-12,8) and (-2,8)

answered
User Hanish Sharma
by
8.5k points
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