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B1 of a trapezoid in which Area = (48x+68) inch squared, Height = 8 in, B2 = (9x + 12) in. what I have so far is 48x +68 = 8 (B1 + 9x +12) what do I do from there???????????????…

B1 of a trapezoid in which Area = (48x+68) inch squared, Height = 8 in, B2 = (9x + 12) in. what I have so far is 48x +68 = 8 (B1 + 9x +12) what do I do from there???????????????…
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B1 of a trapezoid in which Area = (48x+68) inch squared, Height = 8 in, B2 = (9x + 12) in.

what I have so far is

48x +68 = 8 (B1 + 9x +12)

what do I do from there????????????????? the question is asking to solve for Base 1/ B1

asked
User Nullrevolution
by
7.2k points

1 Answer

5 votes

A=(1/2)(b1+b2)h =

=(48x+68)in² = (1/2)( b1+(9x+12))8

=b1= 3x+5

answered
User WhiteLine
by
7.6k points
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