Question

Find the zeros of the function p(x) = -9x^2 + 1

Answer 1

Zeros: 1/3 and -1/3

Explanation:

You can solve this for the zeros by using the factoring method:

p(x) = (-3x-1)(3x-1)

Then, you take each factored equation and set it equal to zero:

-3x-1=0

3x-1=0

Then, solve for zero:

-3x=1 x=-1/3

3x=1 x=1/3

Your zeros are 1/3 and -1/3.