Question

In the question y= 4(x-2)^2 + 1, what is the vertex?order pair form

Answer 1

Vertex is
`(p,q)` and our parabola has vertex form of
`y=a(x-p)^2+q=4(x-2)^2+1` that means the vertex is at
`(2,1)`.

Hope this helps.