Answer:∠1=55° ∠2=55° ∠3=55° ∠4=70° ∠5=55°
Explanation:
We know that opposite angles of rhombus are congruent and the diagonals of rhombus cut the vertex angles into half. So ∠4=70° and ∠2=∠3=∠1=∠5.
Let ∠2+∠3=x
the sum of four angles of rhombus= 360°
70+70+ x +x = 360°
140+2x = 360°
2x=220°
x=110°
∠2=110°/2=55°=∠3=∠1=∠5