asked 33.6k views
9 votes
The radioactive substance uranium-240 has a half-life of 14 hours. The amount

A(t) of a sample of uranium-240 remaining (in grams) after t hours is given by the following exponential function.
At = 3900(1/2) t/14
Find the initial amount in the sample and the amount remaining after 60 hours.
Round your answers to the nearest gram as necessary.

PLEASE HELP ASAP

asked
User VoxPelli
by
8.6k points

1 Answer

7 votes

Answer:

See analyris

Explanation:


Hlug\ in\ the\ value\ of \left.\ t.\right\}


The\ infital\ ampunt\ in\ the\ sample:


t=0_(-1)\ \ \ \ \ f(t)=39\omega\bullet((1)/(2))^(0)/(14)


=3900\ g.


Ater\ bo\ busis.


t=6,\ \ \ \ \ A(t)=2900*((1)/(2))^(60)/(14)


=3900*((1)/(2))^(30)/(7)


\approx 209.

I hope this helps you

:)

answered
User Klarissa
by
8.2k points
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