Question

The tire of his unicycle has a circumference of 2.8m , point,, and the tire revolves 1.51.51, point, 5 times per second. What is the distance Benjamin travels in 100100100 seconds?

Answer 1

Benjamin travels 7 meters in 100 seconds.

Explanation:

We are given the following in the question:

Circumference of tire = 2.8 m

Revolution of time = 1.5 times per minute.

Total time = 100 seconds.

We have to calculate distance covered by Benjamin.

Total number of revolution of tires =

`=\text{Revolution rate}* \text{Time}\\\\=1.5\text{ revolution per minute}* (100)/(60)\text{ minutes}\\\\=2.5 \text{ revolutions}`

Total distance covered by Benjamin =

`=\text{Number of revolution of tires}* \text{Circumference of tire}\\=2.5* 2.8\\=7\text{ meters}`

Thus, Benjamin travels 7 meters in 100 seconds.