Question

A step-up transformer has 50 turns on its primary coil and 2000 turns on its secondary

coil. The primary circuit is supplied with an effective AC voltage of 150 V.
a. What is the voltage in the secondary circuit?
b. If the current in the secondary circuit is 0.24 A, what is the current in the primary
circuit?

Answer 1

Vs= 6000 v

Ip=9.6 A

Step-by-step explanation:

Ns/Np = Vs/Vp

2000/50 = Vs/150

40 x 150 = Vs

Vs= 6000 v

Vs/Vp=Ip/Is

6000/150=Ip /0.24

Ip=9.6 A