Question

A daughter has hemophilia, a recessive sex-linked trait. Which are possible genotypes of her parents?

A. XHxh and Xhy
B. XHXH and xhy
c. xhxh and XHY
D. XHxh and XHY

Answer 1

D. XHxh and XHY

Step-by-step explanation:

since this is the only answer with genes that share a common allele, the answer is D.

In order for a recessive gene to be present, the daughter must have gained the alleles of XHXH, which in this case, is a 25% chance. The other two possibilites are XHxh, XHY, and Yxh. To further prove this, a female must have 2 X alleles and to have hemophilia, they must carry 2 H's. If they were to only have one H, they would be a carrier instead of a product.