A rolling pin has two identical cylindrical handles attached to a larger handle that is 12 inches long. The large cylinder measures 5 inches in diameter and the handles measure …

Question

asked Feb 3, 2021 135k views

1 Answer

Kjp · Answer 1 · 2021-02-07T17:31:36+0000

Answer:

Volume of the rolling pin = 246.09
in^(3)

Explanation:

Length of larger cylinder L = 12 in

Diameter of larger cylinder D = 5 in

Diameter of two handles = 1.5 in

Length of two handles = 3 in

Volume of the rolling pin = Volume of two handles + Volume of larger cylinder

Volume of two handles = 2 (
$\pi r^(2)L$ )

Volume of two handles = 2 (3.14 ×
0.75^(2) × 3 )

Volume of two handles = 10.59
in^(3)

Volume of larger cylinder = (
$\pi r^(2)L$ )

Volume of larger cylinder = (3.14 ×
2.5^(2) × 12 )

Volume of larger cylinder = 235.5
in^(3)

Volume of the rolling pin = 10.59 + 235.5

Volume of the rolling pin = 246.09
in^(3)