Question

Please help me out anyone on the question below. ASAP

Answer 1

a) P(3) = 0.2

b) 0.44

c) 112

Explanation:

a) each set of branches add up to 1:

P(1) + P(2) + P(3) = 1

0.35 + 0.45 + P(3) = 1

P(3) = 1 - 0.8

P(3) = 0.2

P(red) = (0.35×0.6) + (0.45×0.2) + (0.2×0.7) = 0.44

P(black) = 1 - P(red)

= 1 - 0.44 = 0.56

Expected no. of black balls:

200 × 0.56 = 112