How many grams of oxygen are needed to complete the combustion of 8 g of methane, CH4

Question

asked Feb 14, 2021 225k views

1 Answer

Aldana · Answer 1 · 2021-02-19T06:27:53+0000

Answer:

32 grams

Step-by-step explanation:

So 1 mole of methane requires 2 moles of oxygen for complete combustion. So 16 g of Methane requires 64 g of oxygen for the complete combustion.

So 8 g of Methane requires = 8x64/16=32 g of oxygen.