Question

Find the x-intercepts of 2x^2-15x+7=0 using any method. Show as much work as possible for full credit.

Answer 1

`x_1=0.5\\x_2=7`

Explanation:

The Quadratic equation given in the exercise is:

`2x^2-15x+7=0`

In order to solve it and find the x-intercepts, you can apply the Quadratic formula. This is the following:

`x=(-b\±√(b^2-4ac) )/(2a)`

In this case you can identify that:

`a=2\\\\b=-15\\\\c=7`

Knowing these values you can substitute them into the Quadratic formula. Then you must evaluate in order to find the solutions of the Quadratic equation given.

You get the following result:

`x=(-(-15)\±√((-15)^2-4(2)(7)) )/(2(2))\\\\x=(15\±√(225-56) )/(4)\\\\\\x_1=0.5\\x_2=7`