Question

What is the answer for m^2-5m-14=0?

Answer 1

Answer: m = 7 or -2

Explanation:

Quadratic Formula!
`\frac{{-b (+/-)\sqrt{(b^(2)-4ac }}}{2a}`

Polynomial Form:
`ax^(2) +bx+c`

So in this example a: 1 b: -5 c: -14

You get:
`\frac{{-(-5) (+/-)\sqrt{((-5)^(2)-4(1)(-14) }}}{2(1)}`

m = 7 or -2

Check by plugging a value back in for m

`(7)^(2) -5(7)-14=0?\\(-2)^(2) -5(-2)-14=0?\\`

True for both.