Question

Please help me I’m so lost !!!!

Answer 1

`4095`

Explanation:

`\sum _(n=1)^63\left(4^(n-1)\right)\:`

`\sum _(n=1)^63\cdot \:4^(n-1)`

Compute general progression:

`(3\cdot \:4^(\left(n+1\right)-1))/(3\cdot \:4^(n-1))=4`

`r=4\\`

`a_1=3\cdot \:4^(1-1)`

`a_1=3`

nth term is computed by:

`r=4,\:a_n=3\cdot \:4^(n-1)`

plug in the values
`n=6,\:\spacea_1=3,\:\spacer=4`:

`=3\cdot (1-4^6)/(1-4)`

`=4095`