Question

Pls help nothings helping !!

Answer 1

Explanation:

∠BCD=∠DEF=38°(alternate angles)

∠FDE=90-38=52°

Δ BCD≅ΔFED

`(CD)/(sin~90) =(10)/(sin~38) \\CD=(10)/(sin~38) \\(DE)/(sin ~90) =(17)/(sin ~52) \\DE=(17)/(sin~52) \\CE=CD+DE=(10)/(sin~38) +(17)/(sin~52) \\=?`