Question

Please help I have no clue help please

Answer 1

Given:

Given that the graph of the circle with center at the point (-3,1)

The standard form for the equation of the circle is given by

`(x-h)^2+(y-k)^2=r^2`

where (h,k) is the center.

We need to determine the equation of the circle.

Center and Radius:

Let us substitute the center point (-3,1) in the equation of the circle.

Thus, we get;

`(x-(-3))^2+(y-(1))^2=r^2` --------(1)

Now, we shall find the radius of the circle.

The radius of the circle is the distance from the center to any point on the circle.

The radius can be determined by finding the number of units between the center and the point on the circle.

Thus, there are 2 units between the point and the center.

Hence, Radius = 2 units.

Substituting r = 2 in equation (1), we get;

`(x-(-3))^2+(y-(1))^2=2^2`

Thus, the equation of the circle
`(x-(-3))^2+(y-(1))^2=2^2`