Question

2A1 + 3MgCl2 --> 2AlCl3 + 3Mg

How many moles of aluminum chloride are produced from 2.5 moles of magnesium
chloride?

Answer 1

The answer to your question is 1.67 moles

Step-by-step explanation:

Data

moles of AlCl₃ = ?

moles of MgCl₂ = 2.5

Balanced chemical reaction

2Al + 3MgCl₂ ⇒ 2AlCl₃ + 3Mg

Process

To solve this problem using proportions and cross multiplication.

Use the coefficients of the balanced chemical reaction.

3 moles of MgCl₂ ------------------- 2 moles of AlCl₃

2.5 moles of MgCl₂ ----------------- x

x = (2.5 x 2) / 3

-Simplification

x = 5 / 3

-Result

x = 1.67 moles