Question

Pls help :)) this question is confusing for me :)

Answer 1

Given:

`y^(2)(2 y-5)-8 y+20`

To find:

The product of the expression.

Solution:

`y^(2)(2 y-5)-8 y+20=y^(2)(2 y-5)+(-8 y+20)`

Take out -4 as a common factor in Last two terms.

`=y^(2)(2 y-5)-4(2 y-5)`

Make sure the terms in both brackets must be same.

Take out common factor (2y - 5) from both terms.

`=(2 y-5)(y^(2)-4)`

4 can be written as 2².

`=(2 y-5)\left(y^(2)-2^2\right)`

Using the identity:
`(a^2-b^2)=(a-b)(a+b)`

`=(2 y-5)(y-2)(y+2)`.

The product is
`(2 y-5)(y-2)(y+2)`.