Question

12.0 g NaHSO4 is dissolved in water to make a 2.00 L solution.
What is the molarity of the M

Answer 1

0.05M or 0.05moldm⁻³

Step-by-step explanation:

Mass of NaHSO₄ = 12g

Volume of water = 2L

Unknown:

Molarity of the solution = ?

Solution:

The molarity of a solution is the amount of moles of solute dissolved in a given volume of solvent.

Mathematically;

Molarity =
`(number of moles)/(volume)`

Let us find the number of moles of NaHSO₄;

Number of moles =
`(mass)/(molar mass)`

molar mass of NaHSO₄ = 23 + 1 + 32 + 4(16) = 120g/mol

Number of moles of NaHSO₄ =
`(12)/(120)` = 0.1mole

Now;

Molarity =
`(0.1)/(2)` = 0.05M or 0.05moldm⁻³