Question

a cylinder of argon gas contains 50.0 l of ar at 18.4 atm and 127 Celsuis. How many grams are in the cylinder?

Answer 1

11 grams of argon gas

Step-by-step explanation:

PV = nRT

P= 18.4 atm

V = 50 L

n = find moles then use molar mass to convert to grams

R = atm gas constant = 8.314

T = IN Kelvins** = 127 C + 273 = 400 K

molar mass of Ar =40g / mol

18.4(50) = 8.314(400)n

n = .276 mol Ar

.276(40) = 11 grams of Argon Gas