A package that weighs 300 lb is placed on an inclined plane. If a force of 10 lb is just sufficient to keep the package from sliding, find the angle of inclination of the plane.…

Question

asked Oct 23, 2021 44.3k views

1 Answer

Rgahan · Answer 1 · 2021-10-27T11:05:50+0000

Answer:

The angle of inclination of the plane
$\theta$ = 1.91°

Explanation:

Given data

W = 300 lb

Force sufficient to slide the box F = 10 lb

From the free body diagram

W
$\sin \theta$ = F

Put the values in above formula we get

300
$\sin \theta$ = 10

$\sin \theta$ = 0.0333

$\theta$ = 1.91°

This is the angle of inclination of the plane.