How many moles are in a 501mL of a 2.37 M solution of Al2(SO4)3?

Question

asked May 16, 2021 220k views

1 Answer

Patton · Answer 1 · 2021-05-21T18:53:44+0000

The number of moles of Al₂(SO₄)₃ is 1.2 mol

Step-by-step explanation:

Given:

Volume of the solution, V = 501 mL

V = 0.501L

Molarity of the solution, M = 2.37M

Moles, n = ?

We know:

Molarity =
(moles of solute)/(volumeof solution)

On substituting the values we get:

$2.37 = (n)/(0.501) \\\\n = 1.2 mol$

Therefore, the number of moles of Al₂(SO₄)₃ is 1.2 mol