Question

Oxygen gas is collected at a pressure of 1.21 atm in a container which has a volume of 10.0 L. What temperature (in Kelvin) must be maintained on 0.500 moles of this gas in order to maintain this pressure? Round to the nearest whole number (no decimals in your answer).

Answer 1

Answer : The temperature of gas is, 295 K

Explanation :

To calculate the temperature of gas we are using ideal gas equation:

`PV=nRT`

where,

P = Pressure of gas = 1.21 atm

V = Volume of gas = 10.0 L

n = number of moles = 0.500 mole

R = Gas constant =
`0.0821L.atm/mol.K`

T = Temperature of gas = ?

Now put all the given values in above equation, we get:

`1.21atm* 10.0L=0.500mole* (0.0821L.atm/mol.K)* T`

`T=294.8Kapprox 295K`

Therefore, the temperature of gas is, 295 K