asked 105k views
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A simple random sample of size n is drawn from a normally distributed population, and the mean of the sample is x Overbar, while the standard deviation is s. What is the 99% confidence interval for the population mean? Use the table below to help you answer the question.

asked
User Nyxynyxx
by
7.9k points

2 Answers

2 votes

Answer: THE answer ITS b

Explanation:

step one i got it wrong step 2 edge 2022 said b.

answered
User Adam Alexander
by
9.0k points
4 votes

Answer:

CI = x ± 2.58 (s / √n)

Explanation:

The confidence interval is the mean plus or minus the margin of error. The margin of error is the critical value times the standard error. For a normal distribution, the critical value is the z-score at the given confidence level. The standard error is the standard deviation divided by the square root of the sample size.

CI = x ± z (s / √n)

At 99% confidence, z = 2.58.

CI = x ± 2.58 (s / √n)

answered
User Nikhil Ghuse
by
8.1k points
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