Question

The table shows the results of a random survey at Scobey Middle School about students’ favorite cookies. Based on the results from the survey, what percent of students at Scobey Middle like…

1. chocolate chip
2. peanut butter
3. oatmeal
4. sugar
5.raisin

Answer 1

Given:

Random survey of Scobey middle school

To find:

The percent of students like cookies.

Solution:

Total number of cookies = 49 + 12 + 10 + 8 + 3

= 82

Percentage formula:

`$\text{Percentage of part} = \frac{\text{Part}}{\text{Whole} }* 100`

`$\text{Chocolate chip }\%=(49)/(82)*100`

= 59.76%

Percent of student like chocolate chip is 59.76%.

`$\text{Peanut butter}\%=(12)/(82)*100`

= 14.64%

Percent of student like peanut butter is 14.64%.

`$\text{Oatmeal}\%=(10)/(82)*100`

= 12.19%

Percent of student like oatmeal is 12.19%.

`$\text{Sugar}\%=(8)/(82)*100`

= 9.76%

Percent of student like sugar is 9.76%.

`$\text{Raisin}\%=(3)/(82)*100`

= 3.65%

Percent of student like raisin is 3.65%.