Question

Consider a mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 0.09 L. If the combustion of this mixture releases 900. Jof energy, to what volume will the gases expand against a constant pressure of 670. torr if all the energy of combustion is converted into work to push back the piston? (1 atm = 760 torr, 1 L atm = 101.325 J) a. 10.00 L b. 10.17 L c. 1.47 L d. 1.34L

Answer 1

Answer: 10.17 L volume is required for the gases to expand against a constant pressure of 670.

Step-by-step explanation:

The given data is as follows.

`V_(i)` = 0.09 L, P = 670 torr

As, W = 900 J (given)

so, =
`(900)/(101.325 atm L)`

= 8.882 atm L

Now, we will change pressure into atm as follows.

P = 670 torr

=
`(670)/(760)` atm

= 0.8816 atm

Therefore, we will calculate the final volume as follows.

W =
`P(V_(f) - V_(i))`

8.882 =
`0.8816 * (V_(f) - 0.09)`

`V_(f) - 0.09` = 10.08

`V_(f)` = 10.17 L

Thus, we can conclude that 10.17 L volume is required for the gases to expand against a constant pressure of 670.