Question

Which are the solutions of the quadratic equation? x2 = –5x – 3 –5, 0 StartFraction negative 5 minus StartRoot 13 EndRoot Over 2 EndFraction comma StartFraction negative 5 + StartRoot 13 EndRoot Over 2 EndFraction StartFraction 5 minus StartRoot 13 EndRoot Over 2 EndFraction comma StartFraction 5 + StartRoot 13 EndRoot Over 2 EndFraction 5, 0

Answer 1

Answer: B

Explanation:

it is B

Answer 2

Given:

The quadratic equation is
`x^(2)=-5 x-3`

We need to determine the solutions of the quadratic equation.

Solution:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

`x^(2)+5 x+3=0`

The solution of the equation can be determined using quadratic formula.

Thus, we get;

`x=\frac{-5 \pm \sqrt{5^(2)-4 \cdot 1 \cdot 3}}{2 \cdot 1}`

`x=(-5 \pm √(25-12))/(2 )`

`x=(-5 \pm √(13))/(2 )`

Thus, the two roots of the equation are
`x=(-5 + √(13))/(2 )` and
`x=(-5- √(13))/(2 )`

Hence, the solutions of the equation are
`x=(-5 + √(13))/(2 )` and
`x=(-5- √(13))/(2 )`