Question

0.250 mol of octane is allowed to react with 0.860 mol of oxygen. Which is the limiting reactant?How many moles of water are produced in this reaction?

Answer 1

0.619 mol

Step-by-step explanation:

2C8H18 + 25O2 -> 16CO2 + 18H2O

0.25 0.86

0.25/2 > 0.86/25

The limiting reactant is Oxygen

Moles of water = 0.86 mol * 18/25=0.619 mol