Question

(d+6)(2d^2-d+7)

monomials, find the product

Answer 1

2d^3+11d^2+d+42

Explanation:

(d+6)(2d2−d+7)

=(d+6)(2d2+−d+7)

=(d)(2d^2)+(d)(−d)+(d)(7)+(6)(2d^2)+(6)(−d)+(6)(7)

=2d^3−d^2+7d+12d^2−6d+42

=2d^3+11d^2+d+42