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Prove that the following is a right – isosceles triangle.
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Prove that the following is a right – isosceles triangle. Show work-example-1
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User Moondra
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Answer:

Proved down

Explanation:

To prove that a triangle is isosceles use the distance formula to find the length of its side and check if there are two sides equal.

To prove that a triangle is right find the square of the longest side and then find the sum of the squares of the other two sides, if the two answers are equal, then the triangle is right (converse of Pythagoras Theorem).

The formula of the distance between two points is:


d=\sqrt{(x_(2)-x_(1))^(2)+(y_(2)-y_(1))^(2)}

∵ x = (-1 , 5) and y = (4 , 4)


x_(1) = -1 and
x_(2) = 4


y_(1) = 5 and
y_(2) = 4

- Substitute them in the formula of the distance to find xy


xy=\sqrt{(4--1)^(2)+(4-5)^(2)}=√(25+1)


xy=√(26)



∵ x = (-1 , 5) and z = (-2 , 0)


x_(1) = -1 and
x_(2) = -2


y_(1) = 5 and
y_(2) = 0

- Substitute them in the formula of the distance to find xz


xz=\sqrt{(-2--1)^(2)+(0-5)^(2)}=√(1+25)


xz=√(26)

∵ xy = xz

- The isosceles triangle has two equal sides

∴ Δ xyz is an isosceles triangle

∵ y = (4 , 4) and z = (-2 , 0)


x_(1) = 4 and
x_(2) = -2


y_(1) = 4 and
y_(2) = 0

- Substitute them in the formula of the distance to find yz


yz=\sqrt{(-2-4)^(2)+(0-4)^(2)}=√(36+16)


yz=√(52)

yz is the longest side lets find its square

∵ (yz)² = (
√(52)

∴ (yz)² = 52

- Lets find the sum of the squares of the other two sides

∵ (xy)² + (xz)² = (
√(26) )² + (
√(26)

∴ (xy)² + (xz)² = 26 + 26 = 52

∴ (yz)² = (xy)² + (xz)²

- That means the angle opposite to yz is a right angle

Δ xyz is a right isosceles triangle

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User Gpsugy
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