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The number of tickets purchased by an individual for Beckham College's holiday music festival is a uniformly distributed random variable ranging from 2 to 7. Find the mean and standard deviation of this random variable. (Round your answers to 2 decimal places.) Mean Standard deviation

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User Itun
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7.6k points

1 Answer

3 votes

Answer:

The mean is 4.5 and the standard deviation is 1.44.

Explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The mean of the uniform probability distribution is:


M = ((a + b))/(2)

The standard deviation of the uniform probability distribution is:


S = \sqrt{((b-a)^(2))/(12)}

Uniformly distributed random variable ranging from 2 to 7.

This means that
a = 2, b = 7.

So


M = ((2 + 7))/(2) = 4.5


S = \sqrt{((b-a)^(2))/(12)} = \sqrt{((7 - 2)^(2))/(12)} = 1.44

The mean is 4.5 and the standard deviation is 1.44.

answered
User GaetanoM
by
7.4k points
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