A mountain bike tire has a diameter of 26 inches to the nearest foot how far does the tire travel when it makes 32 revolutions and does this require circumference and area?

Question

asked Aug 1, 2021 113k views

1 Answer

Aggietech · Answer 1 · 2021-08-06T07:46:22+0000

The distance it covers in 32 revolution is 217.9 ft .

Explanation:

Given,

The diameter of the tire of the bike = 26 in

The radius (r) = 13 in

To find the distance it travels in 32 revolutions.

To find the revolution we need to find the circumference.

Formula

The circumference of a circle = 2πr

Now,

The circumference of a circle = 2×
(22)/(7) ×13 in

= 81.71 in (approx)

The distance it covers in 32 revolution is = 81.71×32 in

= 2614.85 in

We know that 1 ft = 12 inch

2614.85 in = 2614.85 ÷ 12 ft = 217.9 ft (approx)