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F(x)=0.2(x-2)(x+1)(x-5) determine end behavior

F(x)=0.2(x-2)(x+1)(x-5) determine end behavior
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F(x)=0.2(x-2)(x+1)(x-5) determine end behavior

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User Adam Sheehan
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Answer:

Explanation:

F(x)=0.2(x-2)(x+1)(x-5) determine end behavior-example-1
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User Mobiusklein
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This will result in a cubic form (x^3). 0.2 is positive so it will not change the end behavior as far as direction. The right end behavior with be positive and the left end will be negative.
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User Teatro
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