asked 94.5k views
2 votes
A light bulb factory produces 1,188 light bulbs every hour. Approximately 3.83% of the light bulbs are defective, and do not work. Using the binomial distribution, what is the standard deviation of the number of defective bulbs produced in an hour

1 Answer

2 votes

Answer:

The standard deviation of the number of defective bulbs produced in an hour is 6.615

Explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:


E(X) = np

The standard deviation of the binomial distribution is:


√(V(X)) = √(np(1-p))

In this problem, we have that:


p = 0.0383, n = 1188

What is the standard deviation of the number of defective bulbs produced in an hour


√(V(X)) = √(np(1-p)) = √(1188*0.0383*(1-0.0383)) = 6.615

The standard deviation of the number of defective bulbs produced in an hour is 6.615

answered
User Ron Wertlen
by
8.6k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.