Question

A flatbed truck is supported by its four drive wheels, and is moving with an acceleration of 6.3 m/s2. For what value of the coefficient of static friction between the truck bed and a cabinet will the cabinet slip along the bed surface?

Answer 1

Coefficient of static friction will be equal to 0.642

Step-by-step explanation:

We have given acceleration
`a=6.3m/sec^2`

Acceleration due to gravity
`g=9.8m/sec^2`

We have to find the coefficient of static friction between truck and a cabinet will

We know that acceleration is equal to
`a=\mu g`, here
`\mu` is coefficient of static friction and g is acceleration due to gravity

So
`\mu =(a)/(g)=(6.3)/(9.8)=0.642`

So coefficient of static friction will be equal to 0.642