Question

A solution is created by dissolving 11.5 grams of ammonium chloride in enough water to make 255 mL of solution. How many moles of ammonium chloride are present in the resulting solution

Answer 1

The no. of moles present in one liter solution is 0.843

Step-by-step explanation:

Mass of ammonium chloride = 11.5 gm

Molar mass of ammonium chloride = 53.491 gm

No. of moles

`N = (mass)/(molar \ mass)`

`N = (11.5)/(53.491)`

N = 0.215 moles

`Molarity= (N)/(volume)`

`molarity = (0.215)/(0.255)`

M = 0.843 M

Thus the no. of moles present in one liter solution is 0.843