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Which point is the center of the circle defined by the equation 2+(−9)2=81 x 2 + ( y − 9 ) 2 = 81 2+(−9)2=81 x 2 + ( y − 9 ) 2 = 81 Group of answer choices (0, -9) (-9, 0) (0, 9) (9, 0)

2 Answers

6 votes

Answer:

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Explanation:

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answered
User Jortx
by
8.3k points
5 votes

Answer:

(0, 9)

Explanation:

The circle defined by the equation ...

(x -h)^2 +(y -k)^2 = r^2

has its center at (h, k).

We think your circle's equation is ...

x^2 + ( y − 9 )^2 = 81

so it would have its center where h = 0 and k = 9.

The center is (0, 9).

_____

Comment on the question

Sometimes, copying and pasting seems to cause things to be repeated 3 times, usually in different formats. It would be nice to have one clean copy of the equation, so we can easily tell what it is supposed to be. Editing may be required, to make sure all necessary math symbols are included.

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