Question

What is the temperature of 4.75 moles of a substance at a pressure of 1.2 atm and a volume of 0.125 L? Use 0.0821 for R and significant digits (2 in this case). Report your answer in Kelvin.

Answer 1

T = 0.38 K

Step-by-step explanation:

Given data:

Number of moles = 4.75 mol

Pressure = 1.2 atm

Volume = 0.125 L

R = 0.0821 atm.L /mol.K

Temperature = ?

Solution:

Formula:

PV = nRT

T = PV/nR

T = 1.2 atm × 0.125 L / 4.75 mol × 0.0821 atm.L /mol.K

T = 0.15 / 0.39 /K

T = 0.38 K